x^2+25x-3000=0

Solution for x^2+25x-3000=0 equation:

x^2+25x-3000=0

a = 1; b = 25; c = -3000;
Δ = b2-4ac
Δ = 252-4·1·(-3000)
Δ = 12625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12625}=\sqrt{25*505}=\sqrt{25}*\sqrt{505}=5\sqrt{505}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5\sqrt{505}}{2*1}=\frac{-25-5\sqrt{505}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5\sqrt{505}}{2*1}=\frac{-25+5\sqrt{505}}{2}
$